2490回环句 2023-06-30 字数统计: 92字 | 阅读时长: 1min 题目:[2490]回环句.md 思想:分割每个单词,然后拼接到一起(123拼接成123123),再直接判断每个单词对应的下一个单词是否满足首尾相同即可。 代码:123456789class Solution: def isCircularSentence(self, sentence: str) -> bool: sentence = sentence.split(' ') length = len(sentence) sentence += sentence for i in range(0, length): if sentence[i][-1] != sentence[i+1][0]: return False return True Python 题解 字符串 扫一扫,分享到微信