1604Warn alert person who uses the same employee card within one hour One question daily

topic

Thought：

Pay attention to the data pre -processing of this time question，You can convert time to minutes，You can look at the notes in the code。Thought andylbThe consistency of the big man。
Pay attention to，In fact, use the order directlysortIt’s okay。
python: :=Walrus operator，Can be assigned in judgment
Golang: SScanfSscanfStringstrScanning text，according toformat The format specified by the parameter will save the values ​​of the blank separation that is successfully read in the parameters that successfully passed to the function of this function。
Back to the number of entries for successful scanning and any error encountered。

Code：

class Solution:
    def alertNames(self, keyName: List[str], keyTime: List[str]) -> List[str]:
        ans = set()
        dict1 = defaultdict(list)
        for name, time in zip(keyName, keyTime):
            dict1[name].append(int(time[:2])*60+int(time[3:]))
        print(dict1)
        for i in dict1:
            # definition10：00-11：00Three counts appear，Warn
            if len(dict1[i]) >= 3:
                dict1[i].sort()
                print(dict1[i])
                for j in range(len(dict1[i])):
                    # Traversing the current hour to one hour,It seems to be able to watch the slice directly
                    # for k in range(len(dict1[i]) + 1, len(dict1[i])+3):
                    if j + 2 < len(dict1[i]):
                        # if dict1[i][j:j + 3][0].replace(":", "")[:2]
                        if abs(dict1[i][j:j + 3][-1] -
                            dict1[i][j:j + 3][0]) <= 60:
                            ans.add(i)
                        print(dict1[i][j:j + 3])
        ans = list(ans)
        ans.sort()
        return ans