One question daily 2283

2283.Determine whether the number of a number is equal to the value of the digital position。

class Solution:
    def digitCount(self, num: str) -> bool:
        hash_1 = {}
        for index, i in enumerate(num):
            if int(i) != 0:
                hash_1[str(index)] = int(i)
        hash_2 = Counter(num)
        if hash_1 == dict(hash_2):
            return True
        return False

I read this question for a while，MeaningindexRead，indexAppearnum[index]Second-rate，1210that is”0Appear1Second-rate，”1Appear2Second-rate，”2Appear1Second-rate，”3Appear0Second-rate。ThennumJust count the things in。

Because I was doing the practice of hash table two days ago，So at a glance at this question，Use directlyCounterFunction counts，Compare，Finish